chendan0327
幼苗
共回答了24个问题采纳率:83.3% 举报
∫(0→1) [2xsin(x²) + xe^x] dx
= ∫(0→1) sin(x²) d(x²) + ∫(0→1) x de^x
= - cos(x²)|(0→1) + xe^x|(0→1) - ∫(0→1) e^x dx
= - [cos(1) - cos(0)] + (e - 0) - e^x|(0→1)
= - cos(1) + 1 + e - (e - 1)
= 2 - cos(1)
1年前
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coral526
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http://zhidao.baidu.com/question/505815894.html?quesup2 http://zhidao.baidu.com/question/505821198.html?quesup2 还有2道题帮我解答下吧谢谢