200分求解2道数学方程(1).(4x+5)/(8x-5)=(x-6)/(2x+5) 求x=多少(2).1/(x+3)+

(1) 8x-5!=0, x!=5/8；2x+5!=0, x!=-5/2 (4x+5)(2x+5)=(x-6)(8x=5) 8x^2 +20x+10x+25=8x^2 -5x-48x+30 30x+25=-53x+30 83x=5; x=5/83 (2) x^2 -9!=0, x!=3,x!=-3; 则去掉分母; x-3+4x+12=4x+9 5x+9=4x+9 x=0