qszmy
幼苗
共回答了20个问题采纳率:100% 举报
f(lg5^-1/3)=1+2/2^(lg5^-1/3-1)=k2/(k-1)=2^(lg5^-1/3-lg10)2/(k-1)=2^lg[(5^-1/3)/10]lg[10/(k-1)]=lg[(5^-1/3)/10]所以10/(k-1)=(5^-1/3)/10 100/(k-1)=1/(5^1/3) 5^1/3=(k-1)/100f(lg5^1/3)=1+2/2^(lg5^1/3-1) =1+2/2^{[(k-1)/100]-1}
1年前
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