JAVA编程：已知:s=1-1/2+1/3-1/4+…+1/(n-1)-1/n,编写程序求解n=100时的S值.(用JA

JAVA编程：已知:s=1-1/2+1/3-1/4+…+1/(n-1)-1/n,编写程序求解n=100时的S值.(用JAVA语言编写）,程序哪
public class Exe45
{
public static void main(String args[])
{
double s=1.0000;
for(int i=1;i<=49;i++)
{
s=s+(1/(double)(2*i+1))-(1/(double)(2*i));
}
double sum=s-1/100;
System.out.println("s=1-1/2+...-1/100的和="+sum);
}