已知函数f(x)=根号2sin(2x-π/4)+1,x∈R

1)f(x)=4*√2sin(2x+π/4)+4
当sin(2x+π/4)=1,2x+π/4=π/2+2kπ,x=π/8+kπ时,f(x)取最大值为4*√2+4
当sin(2x+π/4)=-1,2x+π/4=3π/2+2kπ,x=5π/8+kπ时,f(x)取最小值为-4*√2+4
2)f(x)的定义域为R,关于原点对称,
f(x)=4*√2sin(2x+π/4)+4=4sin2x+4cos2x+4
f(-x)=4*√2sin(-2x+π/4)+4=-4sin2x+4cos2x+4
f(-x)!=f(x)
f(-x)!=-f(x)
所以f(x)为非奇非偶函数
求采纳为满意回答.

1)f(x)=4*√2sin(2x+π/4)+4
当sin(2x+π/4)=1，2x+π/4=π/2+2kπ,x=π/8+kπ时，f(x)取最大值为4*√2+4
当sin(2x+π/4)=-1,2x+π/4=3π/2+2kπ,x=5π/8+kπ时，f(x)取最小值为-4*√2+4
2)f(x)的定义域为R，关于原点对称，
f(x)=4*√2sin(2x+π/4)+4...