qq-yyd
幼苗
共回答了23个问题采纳率:95.7% 举报
(1)f(x)=log1/2[√2*sin(x-π/4)]
定义域:(2kπ+π/4 ,2kπ+5π/4)
值域(-∞,-1/2)
(2)f(-x)=log1/2[√2*sin(-x-π/4)] =log1/2[-√2*sin(x+π/4)]
所以他即不是偶函数,也不是奇函数.
(3)在(2kπ+π/4 ,2kπ+3π/4]为增函数,在[2kπ+3π/4,2kπ+5π/4)为减函数.
(4)f(x+2nπ)=log1/2[√2*sin(x+2nπ-π/4)] = log1/2[√2*sin(x-π/4)] = f(x)
∴f(x)为周期函数,其最小正周期:Tmin = 2π
1年前
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