qiaoyuf0504
幼苗
共回答了19个问题采纳率:84.2% 举报
y=sin2x+acos2x cosu=a/√(a^2+1),sinu=1/√(a^2+1)
= √(a^2+1) cos(2x-u)
= √(a^2+1)cos(2(x-u/2))
y对称轴x=u/2=-π/8
u=-π/4 cosu=√2/2 a=1
y对称轴x-u/2=-π x=u/2-π=-π/8
u=7π/4,cosu=√2/2,a=1
y对称轴x-u/2=π x=u/2+π=-π/8
u=-9π/4,cosu=√2/2,a=1
a=1
1年前
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