心儿思雨
幼苗
共回答了7个问题采纳率:100% 举报
根据你的题目,我把你的式子改成标准写法:
y=-sin(x/2)*(1-2(cos(x/4)^2))
所以
y'=-(1/2)*cos(x/2)*(1-2(cos(x/4)^2))-sin(x/2)*(-2*2cos(x/4)*(-sin(x/4))*(1/4))
=-(1/2)*cos(x/2)*(1-2(cos(x/4)^2))-sin(x/2)*(cos(x/4)*sin(x/4))
=-(1/2)cos(x/2)+cos(x/2)*(cos(x/4)^2)-(1/2)*(sin(x/2)^2)
最后答案给你了,写的我真累,哈哈,有不懂得可以继续问我.
1年前
2