soontian
幼苗
共回答了17个问题采纳率:82.4% 举报
(1)、;(2)、(6,3)
(1)把点A(4,0),B(3,
![](https://img.yulucn.com/upload/f/7b/f7b486760656e25d39cc75f820788402_thumb.jpg)
)代入y=kx+b即可求解;
(2)设P点坐标为(a,
![](https://img.yulucn.com/upload/f/a1/fa1688ad9192802aa9e7732cbd57e60b_thumb.jpg)
-6)),根据两三角形面积相等即可求出点P的坐标。
(1)设直线m的解析式为y=kx+b,
∵直线m经过点A、B,
∴把点A(4,0),B(3,
![](https://img.yulucn.com/upload/f/7b/f7b486760656e25d39cc75f820788402_thumb.jpg)
)代入y=kx+b,解得b=-6,k=
![](https://img.yulucn.com/upload/e/70/e7047751ab5bea4663190ec4102bb189_thumb.jpg)
。
∴直线m的解析式为y=
![](https://img.yulucn.com/upload/e/70/e7047751ab5bea4663190ec4102bb189_thumb.jpg)
-6.
(2)∵解 y=-3x+3
y=
![](https://img.yulucn.com/upload/e/70/e7047751ab5bea4663190ec4102bb189_thumb.jpg)
x-6得x=2,y=-3,∴C(2,-3), ∴△ADC的面积=
![](https://img.yulucn.com/upload/6/ce/6ce6561db5b4dc2b728c05e296501d65_thumb.jpg)
×3×|-3|=
设P点坐标为(a,
![](https://img.yulucn.com/upload/f/a1/fa1688ad9192802aa9e7732cbd57e60b_thumb.jpg)
-6)∴△ADP的面积=
![](https://img.yulucn.com/upload/6/ce/6ce6561db5b4dc2b728c05e296501d65_thumb.jpg)
×3×|
![](https://img.yulucn.com/upload/f/a1/fa1688ad9192802aa9e7732cbd57e60b_thumb.jpg)
-6|=
∴a=2(舍去)或a=6, ∴点P的坐标为(6,3).
故答案为(1)直线m的解析式为y=
![](https://img.yulucn.com/upload/e/70/e7047751ab5bea4663190ec4102bb189_thumb.jpg)
-6.(2)(6,3).
1年前
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