赞 dongisking 幼苗
共回答了18个问题采纳率：94.4% 举报
3x^2+axy+by^2+x+9y-4
=(3x^2+6xy-3x)+(a-6)xy+by^2+x+3x+9y-4
=3x(x+2y-1)+(a-6)xy+by^2+(4x+8y-4)+y
=3x(x+2y-1)+(a-6)xy+by^2+4(x+2y-1)+y
=3x(x+2y-1)+4(x+2y-1)+y{(a-6)x+by+1}
所以(a-6)x+by+1是x+2y-1的倍数
所以有a-6=-1,b=-2
a=5,b=-2
=(3x^2+6xy-3x)+(a-6)xy+by^2+x+3x+9y-4
=3x(x+2y-1)+(a-6)xy+by^2+(4x+8y-4)+y
=3x(x+2y-1)+(a-6)xy+by^2+4(x+2y-1)+y
=3x(x+2y-1)+4(x+2y-1)+y{(a-6)x+by+1}
所以(a-6)x+by+1是x+2y-1的倍数
所以有a-6=-1,b=-2
a=5,b=-2
1年前
5
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