求矩阵I-A的逆矩阵,A=(0.134396,0.049018,0.010954,0.0006330.153003,0.
求矩阵I-A的逆矩阵,
A=(0.134396,0.049018,0.010954,0.000633
0.153003,0.448744,0.202484,0.383519
0.061151,0.106204,0.206827,0.111386
0.023946,0.036817,0.039274,0.073269)
求：（I-A）的逆矩阵
A=(0.134396,0.049018,0.010954,0.000633
0.153003,0.448744,0.202484,0.383519
0.061151,0.106204,0.206827,0.111386
0.023946,0.036817,0.039274,0.073269)
求：（I-A）的逆矩阵
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A=[0.134396,0.049018,0.010954,0.000633
0.153003,0.448744,0.202484,0.383519
0.061151,0.106204,0.206827,0.111386
0.023946,0.036817,0.039274,0.073269];
B=diag([1 1 1 1])-A;
inv(B)
答案：
1.1812 0.1182 0.0493 0.0557
0.4223 2.0212 0.5666 0.9048
0.1552 0.2932 1.3518 0.2839
0.0539 0.0958 0.0811 1.1285
LZ也不用“感谢万分”了.再加个几十分也就可以了.
0.153003,0.448744,0.202484,0.383519
0.061151,0.106204,0.206827,0.111386
0.023946,0.036817,0.039274,0.073269];
B=diag([1 1 1 1])-A;
inv(B)
答案：
1.1812 0.1182 0.0493 0.0557
0.4223 2.0212 0.5666 0.9048
0.1552 0.2932 1.3518 0.2839
0.0539 0.0958 0.0811 1.1285
LZ也不用“感谢万分”了.再加个几十分也就可以了.
1年前
3
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