赞 richard2jp 幼苗
共回答了28个问题采纳率：82.1% 举报
增：
2kπ-π/2≤(2π/5)x-π/3≤2kπ+π/2
2kπ-π/6≤(2π/5)x≤2kπ+5π/6
5kπ-5π/12≤x≤5kπ+25π/12
增区间 【5kπ-5π/12,5kπ+25π/12】,k∈Z
减
2kπ+π/2≤(2π/5)x-π/3≤2kπ+3π/2
2kπ+5π/6≤(2π/5)x≤2kπ+11π/6
5kπ+25π/12≤x≤5kπ+55π/12
减区间 【5kπ+25π/12,5kπ+55π/12】,k∈Z
2kπ-π/2≤(2π/5)x-π/3≤2kπ+π/2
2kπ-π/6≤(2π/5)x≤2kπ+5π/6
5kπ-5π/12≤x≤5kπ+25π/12
增区间 【5kπ-5π/12,5kπ+25π/12】,k∈Z
减
2kπ+π/2≤(2π/5)x-π/3≤2kπ+3π/2
2kπ+5π/6≤(2π/5)x≤2kπ+11π/6
5kπ+25π/12≤x≤5kπ+55π/12
减区间 【5kπ+25π/12,5kπ+55π/12】,k∈Z
1年前 追问
10
晕，抱歉， 改一下： 增： 2kπ-π/2≤(2π/5)x-π/3≤2kπ+π/2 2kπ-π/6≤(2π/5)x≤2kπ+5π/6 5k-5/12≤x≤5k+25/12 增区间 【5k-5/12，5k+25/12】，k∈Z 减 2kπ+π/2≤(2π/5)x-π/3≤2kπ+3π/2 2kπ+5π/6≤(2π/5)x≤2kπ+11π/6 5k+25/12≤x≤5k+55/12 减区间 【5k+25/12，5k+55/12】，k∈Z
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