1.丨3a-b+1丨+(3a-b/2)的平方=0,求b的平方/a+b/【(a/a-b-1)(1-b/a+b)】的值
1.丨3a-b+1丨+(3a-b/2)的平方=0,求b的平方/a+b/【(a/a-b-1)(1-b/a+b)】的值
2.1/1*3=1/2(1-1/3),1/3*5=1/2(1/3-1/5),1/5*7=1/2(1/5-1/7)...1/17*19=1/2(1/17-1/19),所以1/1*3+1/3*5+1/5*7+...+1/17*19=1/2(1-1/3)+1/2(1/3-1/5)+1/2(1/5-1/7)+...+1/2(1/17-1/19)=1/2(1-1/19)=9/19
(1).在和式1/1*3+1/3*5+1/5*7+...中第6项为_______,第n项为______;
(2).受此启发,请你解下面的方程
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2x+18