举报
陈海晨曦
因为f(x)=(√2)sin(3x+π/4)+2,向右平移π/2得到g(x),故: g(x)=(√2)sin[3(x-π/2)+π/4]+2=(√2)sin(3x-5π/4) 由2kπ-π/2≦3x-5π/4≦2kπ+π/2,得2kπ+3π/4≦3x≦2kπ+7π/4, 得单增区间为(2/3)kπ+π/4≦x≦(2/3)kπ+7π/12; 由2kπ+π/2≦3x-5π/4≦2kπ+3π/2,得2kπ+7π/4≦3x≦2kπ+11π/4, 得单减区间为:(2/3)kπ+7π/12≦x≦(2/3)kπ+11π/12.