2002/1×3+2002/3×5+2002/5×7+2002/7×9+2002/9×11 简便计算

eric_hi 1年前 已收到3个回答 举报

pjdnlove 幼苗

共回答了18个问题采纳率:100% 举报

1/1×3=(1-1/3)/2
1/3×5=(1/3-1/5)/2
1/5×7=(1/5-1/7)/2
.
.
1/9×11=(1/9-1/11)/2
2002/1×3+2002/3×5+2002/5×7+2002/7×9+2002/9×11
=2002×1/2×(1/1×3+1/3×5+1/5×7+1/7×9+1/9×11)
=2002×1/2×(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)
=2002×1/2×(1-1/11)
=2002×1/2×10/11
=910

1年前

8

liuxiao533 幼苗

共回答了130个问题 举报

1/(1×3)=(1-1/3)*0.5
1/(3×5)=(1/3-1/5)*0.5
1/(5×7)=(1/5-1/7)*0.5
1/(7×9)=(1/7-1/9)*0.5
1/(9×11)=(1/9-1/11)*0.5
2002/1×3+2002/3×5+2002/5×7+2002/7×9+2002/9×11
=2002×【1/(1×3)+1/(3×...

1年前

3

liolia200x 幼苗

共回答了100个问题 举报

1/1×3=(1-1/3)/2
1/3×5=(1/3-1/5)/2
1/5×7=(1/5-1/7)/2
.
.
1/9×11=(1/9-1/11)/2
2002/1×3+2002/3×5+2002/5×7+2002/7×9+2002/9×11
=2002*(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)/2
=2002*(10/11)/2
=910

1年前

1
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