当x=4是,代数式(x-1)/(x的3/4次幂+x1/2次幂)*x的1/2次幂+x的1/4次幂/x的1/2次幂+1*x的

当x=4是,代数式(x-1)/(x的3/4次幂+x1/2次幂)*x的1/2次幂+x的1/4次幂/x的1/2次幂+1*x的1/4次幂+1的值是?
chouchou432 1年前 已收到2个回答 举报
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可可爱草莓 幼苗

共回答了17个问题采纳率：88.2% 举报

(x-1)/(x的3/4次幂+x1/2次幂)*(x的1/2次幂+x的1/4次幂)/(x的1/2次幂+1)*(x的1/4次幂+1)
=[(x^1/2-1)(x^1/2+1)/x^1/2*(x^1/4+1)]*[x^1/4*(x^1/4+1)/(x^1/2+1)(x^1/4+1)]
=(x^1/2-1)/[x^1/4*(x^1/4+1)]
=(x^1/4-1)(x^1/4+1)/[x^1/4(x^1/4+1)]
=(x^1/4-1)/x^1/4
=1-1/x^1/4
=1-1/4^1/4
=1-1/√2
=1-√2/2

1年前

6

爱猪的媛子 幼苗

共回答了1个问题 举报

(x-1)/(x的3/4次幂+x1/2次幂)*(x的1/2次幂+x的1/4次幂)/(x的1/2次幂+1)*(x的1/4次幂+1)
=[(x^1/2-1)(x^1/2+1)/x^1/2*(x^1/4+1)]*[x^1/4*(x^1/4+1)/(x^1/2+1)(x^1/4+1)]
=(x^1/2-1)/[x^1/4*(x^1/4+1)]
=(x^1/4-1)(x^1/4+1)/[x^1/4(x^1/4+1)]
=(x^1/4-1)/x^1/4
=1-1/x^1/4
=1-1/4^1/4
=1-1/√2
=1-√2/2

1年前

0
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