MATLAB中求椭圆与直线的交点为什么交点不在椭圆和直线上?

程序错了吧，解对的肯定在图上三：

clear;clc;

y00=883.3048 ;

x00=110.0967 ;

bb=54.1413 ;

aa= 31.4013 ;

tt= 0.4041 ;

k0= 1.9626 ;

syms x y

ezplot([(x-x00)*cos(tt)+(y-y00)*sin(tt)]^2/(aa^2)+[(x-x00)*sin(tt)-(y-y00)*cos(tt)]^2/(bb^2)-1,[50 180],[750 1000]);

hold on

ezplot(y-y00+100 - k0*(x-x00+100),[50 180],[750 1000]);

[jx jy] = solve('[(x-x00)*cos(tt) + (y-y00)*sin(tt)]^2/(aa^2) + [(x-x00)*sin(tt) - (y-y00)*cos(tt)]^2/(bb^2) - 1',' y-y00+100 - k0*(x-x00+100)','x,y');

jx=eval(jx);

jy=eval(jy);

scatter(jx,jy)