木木微微
幼苗
共回答了1538个问题 举报
y=x-2√x+3
2√x=x-y+3
4x=(x-y+3)^2
4x=x^2+2(3-y)x+(3-y)^2
x^2+2(3-y-4)x+(3-y)^2=0
x^2-2(y+1)x+(3-y)^2=0
x={2(y+1)±√[4(y+1)^2-4(3-y)^2]}/2
x=(y+1)±√[(y+1)^2-(3-y)^2]
x=(y+1)±√(y^2+2y+1-9+6y-y^2)
x=(y+1)±√(8y-8)
x=(y+1)±2√[2(y-1)]
1年前
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