lixiaoqin
春芽
共回答了8个问题采纳率:100% 举报
设安排 x 名工人做甲种零件,y 名工人做乙种零件,z 名工人做丙种零件.
可列方程组:x+y+z = 86 ,(5x)/3 = (4y)/2 = (3z)/1 .
设 (5x)/3 = (4y)/2 = (3z)/1 = k ,可得:x = (3/5)k ,y = (1/2)k ,z = (1/3)k ;
代入 x+y+z = 86 ,可得:(43/30)k = 86 ,
解得:k = 60 ,
可得:x = (3/5)k = 36 ,y = (1/2)k = 30 ,z = (1/3)k = 20 ;
即:安排 36 名工人做甲种零件,30 名工人做乙种零件,20 名工人做丙种零件.
1年前
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