qin123456
幼苗
共回答了13个问题采纳率:100% 举报
MC//EF交AD于P
DN//AB,则N是MC中点,DN=BM/2=X,则,BM=2X
AM=6-2X
AE=Y
据相似,AE:AM=EG:MP=Y:(6-2X)=EF:MC=AF:AC=AF:8=GF:CP
AF=8Y/(6-2X),AM=4,MB=2,X=1,Y/(6-2X)=Y/4
DN:AM=NP:PM=X/(6-2X)=1/4
NP=PM/4
5PM/4=MC/2,PM=2MC/5,NP=MC/10,CP=3MC/5
EG=Y*PM/4=2*Y*PM/20=MP*Y/10
GF=Y*CP/4=3Y*PM/20
EG:GF=(Y*PM/10)/(3Y*PM/20)
=2:3
即,EG=2GF/3
1年前
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