ricklinii
幼苗
共回答了21个问题采纳率:90.5% 举报
0.49,0.5×10
![](https://img.yulucn.com/upload/b/fc/bfcb0407a392f93a21678b07370a8196_thumb.jpg)
,2.4×10
析:①已知物重和浸没在水中的视重,利用F
浮 =G-F可以得到浮力;
②已知物体受到的浮力和水的密度,利用V
排 =
![](https://img.yulucn.com/upload/d/f5/df5a1f5a77b1cbf604f9dfca057fcb9b_thumb.jpg)
得到物体的体积;
③已知物重,可以得到质量;已知质量和体积,利用ρ=
![](https://img.yulucn.com/upload/6/92/692a897eb444c8e796010cb104d13a4a_thumb.jpg)
计算其密度.
(1)物体受到的浮力为
F
浮 =G-F=1.2N-0.71N=0.49N
(2)物体的体积为
V=V
排 =
![](https://img.yulucn.com/upload/d/f5/df5a1f5a77b1cbf604f9dfca057fcb9b_thumb.jpg)
=
![](https://img.yulucn.com/upload/c/a2/ca2595a12d144d681985a0ac2ea26dc7_thumb.jpg)
=0.5×10
-4 m
3(3)物体的质量为
m=
![](https://img.yulucn.com/upload/4/c7/4c73e7f1594e03f6d6c39079a040da32_thumb.jpg)
=
![](https://img.yulucn.com/upload/5/22/5225fc63069bd72ce4e55b16da244d12_thumb.jpg)
≈0.12kg
物体的密度为
ρ=
![](https://img.yulucn.com/upload/6/92/692a897eb444c8e796010cb104d13a4a_thumb.jpg)
=
![](https://img.yulucn.com/upload/d/d6/dd653c38b8426fda409809a962b5634c_thumb.jpg)
=2.4×10
3 kg/m
3故答案为:0.49;0.5×10
-4 m
3 ;2.4×10
3 kg/m
3 .
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1年前
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