purist001
幼苗
共回答了12个问题采纳率:100% 举报
(1)证明见解析;(1)
![](https://img.yulucn.com/upload/d/8c/d8ce930157e0de2b44ef39107ceabeb7_thumb.jpg)
;5.
试题分析:(1)根据菱形的性质得出∠DAP=∠PAB,AD=AB,再利用全等三角形的判定得出△APB≌△APD;
(2)①首先证明△DFP≌△BEP,进而得出
![](https://img.yulucn.com/upload/f/00/f00705f4ae9ca6649fb9e7536ddbcc5e_thumb.jpg)
,
![](https://img.yulucn.com/upload/c/62/c62202048dafbf6ffaaeaf2172c8342c_thumb.jpg)
,进而得出
![](https://img.yulucn.com/upload/3/8a/38a6139a4e54489a187d5f5f9091071a_thumb.jpg)
,即
![](https://img.yulucn.com/upload/1/d6/1d6306a394c509ca6157fc9ad4d757ac_thumb.jpg)
,即可得出答案;
②根据①中所求得出PF=PE=4,DP=PB=6,进而得出
![](https://img.yulucn.com/upload/d/08/d08952b4066c2dfc8be266a5aa448018_thumb.jpg)
,求出即可.
试题解析:(1)证明:∵点P是菱形ABCD对角线AC上的一点,
∴∠DAP=∠PAB,AD=AB,
∵在△APB和△APD中
![](https://img.yulucn.com/upload/d/a6/da62ec8097ecf601814c99d04c545190_thumb.jpg)
,
∴△APB≌△APD(SAS);
(2)①∵△APB≌△APD,
∴DP=PB,∠ADP=∠ABP,
∵在△DFP和△BEP中,
![](https://img.yulucn.com/upload/f/81/f81669653536f4bb3049f84002e1814f_thumb.jpg)
,
∴△DFP≌△BEP(ASA),
∴PF=PE,DF=BE,
∵四边形ABCD是菱形,
∴GD∥AB,
∴
![](https://img.yulucn.com/upload/8/2e/82ebb76f0842bcd110341843577f1448_thumb.jpg)
,
∵DF:FA=1:2,
∴
![](https://img.yulucn.com/upload/f/00/f00705f4ae9ca6649fb9e7536ddbcc5e_thumb.jpg)
,
![](https://img.yulucn.com/upload/c/62/c62202048dafbf6ffaaeaf2172c8342c_thumb.jpg)
,
∴
![](https://img.yulucn.com/upload/e/ac/eac42dcec1cc4a4b266442d178817812_thumb.jpg)
,
∴
![](https://img.yulucn.com/upload/3/8a/38a6139a4e54489a187d5f5f9091071a_thumb.jpg)
,即
![](https://img.yulucn.com/upload/1/d6/1d6306a394c509ca6157fc9ad4d757ac_thumb.jpg)
,
∴
![](https://img.yulucn.com/upload/d/8c/d8ce930157e0de2b44ef39107ceabeb7_thumb.jpg)
;
②当x=6时,
![](https://img.yulucn.com/upload/4/18/418bfdc0a6ebad2872a1262b9d0804e9_thumb.jpg)
,
∴PF=PE=4,DP=PB=6,
∵
![](https://img.yulucn.com/upload/d/08/d08952b4066c2dfc8be266a5aa448018_thumb.jpg)
,
∴
![](https://img.yulucn.com/upload/e/ed/eed09eec071186aedf00c6042fbb0b3a_thumb.jpg)
,
解得:FG=5,
故线段FG的长为5.
1年前
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