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设PO和AC的交点为H
H为AC中点,
三角形DHF和AHO相似,2DF=AO=R
2FH = HO
根据勾股定理,
DF^2 =DH^2+FH^2
=(R-HO)^2+FH^2
5*5 = (10-2FH)^2 +FH^2
解得 FH =5 或 3
FH =5,H点与O点重合,C与B重合,不合题义
FH = 3,DG= 4
三角形AOH和DOE全等
AH = DE = 8
AC = 2AH = 16
BC = 12
三角形DGH和BGC相似
DG = 4,BC = 12 = 3DG
CG=3GH
CG+GH = HC = 1/2 AC = 8
CG = 6
1年前
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