A sampling distribution problem?A random sample of size 81 i
A sampling distribution problem?A random sample of size 81 is drawn from a population with a stand A random sample of size 81 is drawn from a population with a standard deviation of 16.If only 18% of the time a sample mean greater than 300 is obtained,what is the mean of the population?
Assume K= the mean of the parameter the mean of sample~N(K,256/81) convert normal distribution into standard normal distribution Z=(300-K)/(16/9) P(z<(300-K)/(19/9))=1-18% according to standard normal distribution table:(300-K)/(16/9)=0.915 K=298.4