百度提问设向量An=（cosnπ/6,sinnπ/6),n属于正整数,向量b=（1,根号3）则求y=|A1+b|+.|A

A1=(√3/2,1/2) |A1+b|=√(5+2√3)
A2=(1/2,√3/2) |A2+b|=6
A3=(0,1) |A3+b|=√5+2√3)
A4=(-1/2,√3/2) |A4+b|=2√7
A5=(-√3/2,1/2) |A5+b|=2√5
A6=(-1,0) |A6+b|=√3
A7=(-√3/2,-1/2) |A7+b|=√(5-2√3)
A8=(-1/2,-√3/2) |A8+b|=1
A9=(0,-1) |A9+b|=√(5-2√3)
A10=(-√3/2,-1/2) |A10+b|=√(5-2√3)
y=2√(5+2√3)+3√(5-2√3)+2√7+2√5+√3+7