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在322gNa2SO4*10H2O中所含Na离子的质量是46克?所含水分子的数目是10NA
M(Na2SO4.10H2O)=
(23*2+32+16*4+10*18)g/mol=322g/mol
n(Na2SO4.10H2O)=322g/(322g/mol)=1mol
n(Na+)=2n(Na2SO4.10H2O)=2mol
m(Na+)=2mol*23g/mol=46g
M(Na2SO4.10H2O)=
(23*2+32+16*4+10*18)g/mol=322g/mol
n(Na2SO4.10H2O)=322g/(322g/mol)=1moM(Na2SO4.10H2O)=
(23*2+32+16*4+10*18)g/mol=322g/mol
n(Na2SO4.10H2O)=322g/(322g/mol)=1mol
n(Na+)=2n(Na2SO4.10H2O)=2mol
m(Na+)=2mol*23g/mol=46g
n(H2O)=10n(Na2SO4.10H2O)=10mol
所含水分子的数目=10*NA=10NA
1年前
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