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共回答了1627个问题 举报
∫[cos(2x+1)]^5dx
= (1/2)∫ [cos(2x+1)]^4 d sin(2x+1)
=(1/2)∫ {1-2(sin(2x+1))^2+ [sin(2x+1)]^4} d sin(2x+1)
=(1/2)[ sin(2x+1) - 2(sin(2x+1))^3/3 + [sin(2x+1)]^5/5 ] +C
= (1/2)∫ [cos(2x+1)]^4 d sin(2x+1)
=(1/2)∫ {1-2(sin(2x+1))^2+ [sin(2x+1)]^4} d sin(2x+1)
=(1/2)[ sin(2x+1) - 2(sin(2x+1))^3/3 + [sin(2x+1)]^5/5 ] +C
1年前
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