风卷长衣
春芽
共回答了12个问题采纳率:100% 举报
f(3-x)=f(3+x)
f(2)=f(4) 0= -12(16+4m+n)
f(1)=f(5) 3(1+m+n)=-21(25+5m+n)
解得 m = -12, n = 32
f(x)=(4-x^2)(x^2-12x+32)=-(x+2)(x-2)(x-4)(x-8)
=-[(x-3)-5][(x-3)-1][(x-3)+1][(x-3)+5]
=-[(x-3)^2-25][(x-3)^2-1]
=-(x-3)^4+26(x-3)^2-25
=-[(x-3)^2-13]^2+144≤144
最大值为144.
1年前
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