化简求值:[(x^2-x)/(x^2-2x+1)]-[x/(x+1)] 其中x=根号2

三金儿 1年前 已收到1个回答 举报

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/>[(x^2-x)/(x^2-2x+1)]-[x/(x+1)]
=[x(x-1)/(x-1)²]-[x/(x+1)]
=x/(x-1)-x/(x+1)
=x[1/(x-1)-1/(x+1)]
=x[(x+1-x+1)/(x-1)(x+1)]
=x[2/(x²-1)]
=2x/(x²-1)]
=2√2/(2-1)
=2√2

1年前

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