qwertt10
春芽
共回答了14个问题采纳率:92.9% 举报
∫[1/e---->e] |ln³x/x| dx
=∫[1/e---->1] |ln³x/x| dx+∫[1---->e] |ln³x/x| dx
=-∫[1/e---->1] ln³x/x dx+∫[1---->e] ln³x/x dx
=-∫[1/e---->1] ln³x d(lnx)+∫[1---->e] ln³x d(lnx)
=-(1/4)ln⁴x |[1/e---->1] + (1/4)ln⁴x |[1---->e]
=1/4+1/4
=1/2
1年前
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