用VB编程设计一个类似于Windows附件中的计算器,如图所示,可进行简单的算术运算、三角函数和自然对数运算

用VB编程设计一个类似于Windows附件中的计算器,如图所示,可进行简单的算术运算、三角函数和自然对数运算

求代码,如果每条代码后面有说明就更好了,可以追加100
810218 1年前 已收到1个回答 举报

ningweimei 幼苗

共回答了17个问题采纳率:100% 举报

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Dim pi As Double
Dim temp As Double
Dim j As Integer
Dim te As String
Dim yf As String
Dim m As Boolean
Dim f As Boolean
Private Sub Command1_Click(Index As Integer)
If f = True Then Text1 = ""
If Index = 10 Then
Text1.Text = Text1.Text & "."
Else
Text1.Text = Text1.Text & Index
End If
f = False
End Sub
Private Sub Command2_Click(Index As Integer)
Call kl
temp = Text1
Text1 = ""
Text1 = Command2(Index).Caption
f = True
yf = Command2(Index).Caption
End Sub
Private Sub Command3_Click()
If m = True Then
Call kl
Else
Select Case yf
Case "+"
Text1 = temp + Val(Text1)
Case "-"
Text1 = temp - Val(Text1)
Case "*"
Text1 = temp * Val(Text1)
Case "/"
If Val(Text1) = 0 Then
MsgBox "除数不为0"
Else
Text1 = temp / Val(Text1)
End If
End Select
End If
End Sub
Sub kl()
If m = True Then
a = Val(Replace(Text1,te,""))
If te = "sin" Then
If Option1.Value = True Then
Text1 = Sin(a * pi / 180)
Else
a = Val(Replace(Text1,"π/",""))
Text1 = Sin(pi / a)
End If
ElseIf te = "sprt" Then
Text1 = Sqr(a)
ElseIf te = "1/x" Then
Text1 = 1 / a
ElseIf te = "%" Then
Text1 = a * 100
ElseIf te = "cos" Then
If Option1.Value = True Then
Text1 = Cos(a * pi / 180)
Else
a = Val(Replace(Text1,"π/",""))
Text1 = Cos(pi / a)
End If
ElseIf te = "tan" Then
If Option1.Value = True Then
Text1 = Tan(a * pi / 180)
Else
a = Val(Replace(Text1,"π/",""))
Text1 = Tan(pi / a)
End If
ElseIf te = "ln" Then '等号的ln计算
Text1 = Log(Val(Text1.Text))
End If
m = False
End If
End Sub
Private Sub Command4_Click()
Text1.Text = Mid(Text1,1,Len(Text1.Text) - 1)
End Sub
Private Sub Command5_Click()
Text1.Text = ""
temp = 0
m = False
End Sub
Private Sub Command6_Click(Index As Integer)
Text1.Text = Command6(Index).Caption
te = Command6(Index).Caption
m = True
End Sub
Private Sub Command7_Click()
End
End Sub
Private Sub Command8_Click()
Text1 = "π/"
End Sub
Private Sub Form_Load()
pi = 4 * Atn(1)
End Su

1年前

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