6688802
幼苗
共回答了23个问题采纳率:95.7% 举报
首先根据(2a)^x=a,log3a2a=y
得到2^x=a^(1-x),3^y=2*a^(1-y)
2^(1-xy) / 3^(y-xy)=[2/2^(xy)]/[3^(y(1-y))]={2/a^[(1-x)y}/[2*a^(1-y)]^(1-x)=2/{a^(y-xy)*[2*a^(1-y)]^((1-x)=2^x/a^(1-x)=2^x/2^x=1
即2^(1-xy) / 3^(y-xy)=1,所以2^(1-xy)=3^(y-xy).
1年前
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