第一题,要过程,是因式分解哦,谢谢

(x²+3x+2)(4x²+8x+3)-90
=(x+1)(x+2)(2x+1)(2x+3)-90
=[(x+1)(2x+3)][(x+2)(2x+1)]-90
=(2x²+5x+2)(2x²+5x+3)-90
=[(2x²+5x)+2][(2x²+5x)+3]-90
=(2x²+5x)²+5(2x²+5x)+6-90
=(2x²+5x)²+5(2x²+5x)-84
=(2x²+5x-7)(2x²+5x+12)
=(x-1)(2x+7)(2x²+5x+12)
(2x²-3x+1)²-22x²+33x-1
=(2x²-3x+1)²-22x²+33x-11+10
=(2x²-3x+1)²-11(2x²-3x+1)+10
=(2x²-3x+1-10)(2x²-3x+1-1)
=(2x²-3x-9)(2x²-3x)
=x(x-3)(2x+3)(2x-3)
(x-3)(x-1)(x+2)(x+4)+24
=(x-3)(x+4)(x-1)(x+2)+24
=(x²+x-12)(x²+x-2)+24
=(x²+x)²-14(x²+x)+24+24
=(x²+x)²-14(x²+x)+48
=(x²+x-6)(x²+x-8)
=(x²+x-8)(x+3)(x-2)
(x+y)³+2xy(1-x-y)-1
=[(x+y)³-1]+2xy(1-x-y)
=(x+y-1)[(x+y)²+(x+y)+1]-2xy(x+y-1)
=(x+y-1)(x²+y²+x+y+1)