lysee_0
幼苗
共回答了23个问题采纳率:95.7% 举报
(√a-√b)/(√a+√b)+[√a/(a+√ab) -√b/(b-√ab)]/(1/√b)
=(√a-√b)^2/(a-b)+[1/(√a+√b) -1/(√b-√a)]/(1/√b)
=(√a-√b)^2/(a-b)+[1/(√a+√b)+1/(√a-√b)]/(1/√b)
=(√a-√b)^2/(a-b)+[(√a-√b+√a+√b)/(a-b)]/(1/√b)
=(√a-√b)^2/(a-b)+[(2√a)/(a-b)]/(1/√b)
=(√a-√b)^2/(a-b)+2√(ab)/(a-b)
=[a+b-2√(ab)]/(a-b)+2√(ab)/(a-b)
=(a+b)/(a-b)
1年前
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