数学分式的解方程

1、2x(x-2)+x(2x-1)=2(2x-1)(x-2)
2x²-4x+2x²-x=4x²-10x+4
5x=4
x=4/5
2、-12-(3x+1)²=-(3x-1)²
-12-9x²-6x-1=-9x²+6x-1
-12x=12
x=-1
3、1-1/(x-2)-1+1/(x-4)=1-1/(x-6)-1+1/(x-8)
1/(x-4)-1/(x-2)=1/(x-8)-1/(x-6)
(x-2-x+4)/(x-2)(x-4)=(x-6-x+8)/(x-6)(x-8)
-2/(x-2)(x-4)=-2/(x-6)(x-8)
(x-2)(x-4)=(x-6)(x-8)
x²-6x+8=x²-14x+48
8x=40
x=5
bx+a²b=ax+ab²
a²b-ab²=ax-bx
(a-b)x=ab(a-b)
∵a≠b
∴x=a