已知：a²+2a-1=0,求1/(a+1)-(a+3)/(a²-1)×（a²-2a+1)/

已知：a²+2a-1=0,求1/(a+1)-(a+3)/(a²-1)×（a²-2a+1)/(a²+4a+3)的值
tiy723177057 1年前 已收到2个回答 举报
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jylsyh 幼苗

共回答了20个问题采纳率：80% 举报

a²+2a-1=0
a²+2a=1
a²+2a+1=2
(a+1)²=2
1/(a+1)-(a+3)/(a²-1)×（a²-2a+1)/(a²+4a+3)
=1/(a+1)-(a+3)/[(a+1)(a-1)]×(a-1)²/[(a+1)(a+3)]
=1/(a+1)-(a-1)/(a+1)²
=[a+1-(a-1)]/(a+1)²
=2/(a+1)²
=2/2
=1

1年前

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CTermIII 幼苗

共回答了14个问题 举报

先对1/(a+1)-(a+3)/(a²-1)×（a²-2a+1)/(a²+4a+3)进行化简
1/(a+1)-(a+3)/(a²-1)×（a²-2a+1)/(a²+4a+3)
=1/(a+1)-(a+3)/[(a+1)(a-1)]×(a-1)²/[(a+1)(a+3)]
=1/(a+1)-(a-1)/(a...

1年前

1
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